A:3x²-xy B: -2y C: 3x a) (A×B)×C = [(3x²-xy) × (-2y)] × 3x = (-6x²y+2xy²) × 3x = -18x³y+6x²y² b) A×(B×C) = (3x²-xy) × [(-2y) × 3x] = (3x²-xy) × (-6xy) = -18x³y+6x²y² c) (A+B)×C = [(3x²-xy)+(-2y)] × 3x = (3x²-xy-2y) × 3x = 9x³-3x²y-6xy d) A×C+B×C = (3x²-xy) × 3x + (-2y) × 3x = 9x³-3x²y-6xy
A:3x²-xy B: -2y C: 3x (A×B)×C [(3x²-xy)(-2y)]3x= [-6x²y+2xy²]3x=-18x³y+6x²y² A×(B×C) 3x²-xy(-2y*3x)=3x²-xy * -6xy= -18x³ + 6x²y² (A+B)×C [3x²-xy + (-2y)]3x=9x³ - 3x²y -6xy A×C+B×C (3x²-xy)*3x + (-2y)*3x = 9x³-3x²y - 6xy .. nie jestem pewna czy dobrze.. sprawdz..^^
