-(x-4) ^{2} -(x+4)(x-4)=0 -(x-3)(x+3)-(2x-1) ^{2}=x(6-3x)-9 -2+(x+2) ^{2} =2x ^{2} - (x+1) ^{2} tam gdzie jest ^- to do potęgi ^{2} za rozwiązanie daje naj.......

-(x-4)² -(x+4)(x-4)=0 -x²+8x-16-x²+16 8x=16 x=0 (x-3)(x+3)-(2x-1)²=x(6-3x)-9 x²-9-4x²+4x-1=6x-3x²-9 -10+4x=6x-9 -2x=1 x=-½ -2+(x+2)²=2x ²- (x+1)² -2+x²+4x+4=2x²-x²-2x-1 2+4x=-2x-1 2+6x=-1 6x=-3 x=-½

(x-4)²-(x+4)(x-4)=0 x²-8x+16-(x²-16)=0 x²-8x+16 -x² +16 = 0 -8x=32 /:(-8) x=-4 (x-3)(x+3)-(2x-1)²=x(6-3x)-9 (x²-9)-(4x²-4x+1)=6x-3x²-9 x²+9-4x²+4x-1=6x-3x²-9 x²-4x²+4x-6x+3x²=1-9-9 -2x=-17 /:(-2) x=8,5 2+(x+2)² =2x ² - (x+1)² 2+x²+4x+4=2x² -(x²+2x+1) 2+x²+4x+4=2x² -x²-2x-1 x²+4x-2x²+x²+2x=-2-4-1 6x=-7 /:6 x = - 1 1/6 koniec..;D