x²+3x-4<0

a = 1 b = 3 c = -4 Δ = b² - 4ac Δ = 3² - 4(-4*1) = 9 + 16 = 25 √Δ = √25 = 5 x1 = (-b - √Δ) / 2a = (-3 -5) / 2= -4 x2 = (-b + √Δ) / 2a = (-3 + 5) / 2 = 1 x należy do przedziału (-4,1)

x²+3x-4<0 x²+3x-4=0 Δ=b²-4ac=3²-4*1*(-4)=9+16=25 x₁=-b-∫Δ /2a= -3-5 /2= -8/2=-4 x₂=-b+∫Δ /2a= -3+5 /2= 2/2=1 x∈(-4;1)