1. { 10(y+2)+3(x-5)= x-5 { 25(y+2)+3(x-5)= -10 { 10y+20+3x-15= x-5 { 25y+50+3x-15= -10 { 10y +2x = -10 z tego wyznaczamy x więc 2x = -10y-10 / 2 { 25y + 3x= -45 x = -5y-5 {x = -5y-5 {25y + 3(-5y-5) = -45 {x = -5y-5 {25y -15y-15 = -45 {x = -5y-5 {10y= -30 / 10 {x = -5y-5 (y= -3 {x = -5(-3) -5 {y=-3 {x = -15-5 {y=-3 {x= -20 {y=-3 2. rozwiązałam robiąc w drugim równaniu = 32 zamiast -32 jeżeli powinno być -32 to pisz to poprawię { 2(2x-y)+3(x+3y)= 42 { 5(x+3y)-8(2x-y) = -32 { 4x-2y+3x+9y= 42 { 5x+15y -16x+8y =-32 { 7x+7y = 42 /7 {-11x+ 23y = -32 { x+y = 6 z tego wyznaczamy x więc x= 6-y {-11x+ 23y = -32 { x= 6-y {-11(6-y)+ 23y = -32 { x= 6-y {-66 + 11y+ 23y = -32 { x= 6-y {34y = 34 / 34 { x= 6-y {y = 1 { x= 6-1 {y = 1 { x= 5 {y = 1
