3(x-0,5)+2(y+3)=3,5 (3x-1)/3-(y+3)/2=-1

3(x-0,5)+2(y+3)=3,5 (3x-1)/3-(y+3)/2=-1
Odpowiedź

3(x-0,5)+2(y+3)=3,5 (3x-1)/3-(y+3)/2=-1 /*6 3x -1,5 +2y +6 = 3,5 2(3x-1) -3(y +3) = - 6 3x + 2y = 3,5 - 4,5 6x -2 -3y -9 = -6 3x +2y = -1 6x - 3y = -6 + 11 3x= -1 -2y 6x - 3y = 5 x = 1/3(-1-2y) 6*1/3(-1-2y) -3y = 5 x = 1/3(-1-2y) 2(-1-2y) -3y = 5 x = 1/3(-1-2y) -2 -4y -3y = 5 x =1/3(-1-2y) -7y = 5 +2 x = 1/3(-1-2y) y = 7 : (-7) x = 1/3(-1-2y) y = - 1 x = 1/3[ -1 -2*(-1)] y = - 1 x = 1/3[ -1 + 2] y = - 1 x = 1/3*1 y = - 1 x = 1/3 y = - 1

3(x-0,5)+2(y+3)=3,5 (3x-1)/3-(y+3)/2=-1 /*6 3x-1,5+2y+6=3,5 6x-2-3y-9=-6 3x+2y=-1 /(-2) 6x-3y=5 -6x-4y=2 6x-3y=5 _________ -7y=7 y=-1 x=1/3

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