2x-3/x+1 -1=x/x-2
2x-3/x+1 -1=x/x-2
Obliczam dziedzinę: x+1=0 x=-1 x-2=0 x=2 D=R/{-1,2} 2x-3/x+1 -1=x/x-2 |*(x+1)(x-2) (2x-3)(x-2)-1(x+1)(x-2)=x(x+1) 2x²-4x-3x+6-x²+2x-x+2=x²+x x²-x²-6x-x=-8 -7x=-8 |:(-7) x=8/7=1 1/7