Zapisz w jak najprostszej postaci. a) (a+b)-(2a-b)-(a-2b)-= b)(3x-y+1)-(x+y)+(y-x)= c)-(kx+ny)-(3kx+2ny)+(5kx-3ny)= d)(2ab+a+3)-(3ab-a+3)= PILNE!!!!! PROSZE O ODPOWIEĆ!!

a) (a+b)-(2a-b)-(a-2b)-= = a+b-2a+b-a+2b = = -2a+4b b)(3x-y+1)-(x+y)+(y-x)= =3x-y+1-x-y+y-x= =x-y+1 c)-(kx+ny)-(3kx+2ny)+(5kx-3ny)= = -kx-ny-3kx-2ny+5kx-3ny= =kx-6ny d)(2ab+a+3)-(3ab-a+3)= =2ab+a+3-3ab+a-3= =-ab+2a