1) Doprowadź do najprostszej postac a) (2+a)²+(2-a)²-2²-a²= b) (2x+4)²-4x²-16= c) 9x²-25+(3x-5)(3x+5)-2x= d) (7-y)²+(y+7)²+1= 2 Rozwiąż równanie a (x-1)(x-1)+x²-1=2x²-2 b (x+4)²=(x-2)(x+2) c x²+(3x-3)(x+1)=1+(2x-1)²

1) a) (2+a)²+(2-a)²-2²-a²= = 4+4a+a²+4-4a+a²-4-a²= =4+a² b) (2x+4)²-4x²-16= = 4x²+16x+16-4x²-16= =16x c) 9x²-25+(3x-5)(3x+5)-2x= = 9x²-25+9x²-25-2x= =18x²-50-2x d) (7-y)²+(y+7)²+1= =49-14y+y²+y²+14y+49+1= =99+2y² 2 a (x-1)(x-1)+x²-1=2x²-2 x²-x-x+1+x²-1 = 2x²-2 -2x = -2 / (-2) x = 1 b (x+4)²=(x-2)(x+2) x²+4x+16 = x²-4 4x = -20 / 4 x = -5 c x²+(3x-3)(x+1)=1+(2x-1)² x²+3x²+3x-3x-3 = 1+4x²-4x+1 4x = 5 / 4 x = 1¼