Oblicz wartosci funkcji f(0),f(-1 1/2),f(√2),f(√3+1),f(π),f(k) gdy jest okreslona wzorem: a)f(x)=2√3x b)f(x)= I x-√2 I c)f(x)=1/x²-1

f(0),f(-1½),f(√2),f(√3+1),f(π),f(k) a)f(x)=2√3x f(0) = 2√3*0 = 0 f(-1½) = 2√3*(-1½) = -3√3 f(√2) = 2√3*√2 = 2√6 f(√3+1) = 2√3*√3+1 = 2*3+1 = 7 f(π) = 2√3*π = 2√3π f(k) = 2√3*k = 2√3k b)f(x)= Ix-√2I f(0) = I0-√2I = √2 f(-1½) = Ix-√2I = |-1½-√2| = 1½-√2 f(√2) = |√2-√2| = 0 f(√3+1) = |√3+1-√2| = √3+1-√2 nie wiem cy to jest dobrze, pokrecone jakies przyklady ;p