Oblicz pH roztworu wodorotlenku sodu o stężeniu 0,0001 mol/dm3

NaOH ---->Na(+) + OH(-) [NaOH] = [OH-] = 10^-4mol/dm3 pOH = -log[OH-] pOH = -log10^-4 pOH = 4 pH + pOH = 14 pH = 10