Rozwiąż układ równań -(3x+y)²+(√3x-2)(√3x+2)=6y(1- x)-9x(x+2)+y(1-y)+10 -(√2y-2)(√2y+2)+3(x+y)=x(6-y)+xy daje naj... z góry thx

-(3x+y)²+(√3x-2)(√3x+2)=6y(1- x)-9x(x+2)+y(1-y)+10 -(√2y-2)(√2y+2)+3(x+y)=x(6-y)+xy -(9x²+6xy+y²)+3-4=6y-6xy-9x²-18x+y-y²+10 -(2-4)+3x+3y=6x-xy+xy -9x²-6xy-y²-1=6y-6xy-9x²-18x+y-y²+10 -2+4+3x+3y=6x-xy+xy -1=7y-18x+10 2+3x+3y=6x -7y+18x=11 -2x+3y=-2 18x-7y=11 -2x+3y=-2/*9 18x-7y=11 -18x+27y=-18 20y=-7 y=-7/20 y=-7/20 -2x+3*(-7/20)=-2 y=-7/20 -2x-21/20=-2 y=-7/20 -2x=-2+21/20 y=-7/20 -2x=0,95 y=-7/20 x=-0,475