Napisz w formie czstkowej i jonowej równania reakcji: a) CH3COOH+NaOH b) HCOOH+Ca c) (CH3COO)2Ba+Na2Co3

a) CH₃COOH+NaOH = CH₃COONa +H₂O CH₃COO⁻ +H⁺ + Na⁺ +OH⁻ = CH₃COO⁻ + Na⁺ + H₂O b) 2HCOOH+Ca = (HCOO)₂Ca +H₂ 2HCOO⁻ +2H⁺ +Ca = 2HCOO⁻ +Ca²⁺ + H₂ c) (CH₃COO)₂Ba+Na₂CO₃ = 2CH₃COONa + BaCO₃ 2CH₃COO⁻ + Ba²⁺ +2Na⁺ +CO₃²⁻ = 2CH₃COO⁻ +2Na⁺ + BaCO₃