wykaz ze ciag (an)jest rosnacy; n an=----- n+4 wykaz ze ciag (an)jest monotoniczny; an=n^-2n 3n an=-------- n+2 n an=------- 2n-1 3n+2 an=------- 4n+1

n an=...... n+4 n+1 an+1=.... n+5 an+1-an=0 an=an+1 n n+1 ....= .... n+4 n+5 n(n+5)=(n+4)(n+1) n^+5n=n^+n+4n+4 0=4 4>0 an=n^-2n an+1= (n+1)^-2(n+1)=n^+1-2n+2=n^-2n-1 delta=2^+4*1*1=16 3n an=.... n=2 3(n+1) 3n+3 an+1=....... =......=3 (n+1)+2 n+3 n an=.... 2n-1 n+1 n 1 an+1=.........=....=... 2(n+1)-1 2n 2 3n+2 an=..... 4n+1 3(n+1)+2 3n+3+2 3n+5 3 an+1=............=...........=........= ..... 4(n+1)+1 4n+4+1 4n+5 4