OBLICZ a) -(-(-4))*[8-(-5)*(-2)+(-4)*7]:[-(-4)+11]= b) -(-(-(-5)))+(-4)*(8-12)-(-(-(-3)))*(-12):(-(-6))= c) -[-(-10+17)-8]:[-4+3*(-5)*(-2);10-2]+(-7)= W pierwszym ma być-8 w drugim 27 a w trzecim -12 Prosze o szybkie rozwiązanuie dam naj

a) -(-(-4))*[8-(-5)*(-2)+(-4)*7]:[-(-4)+11]=-4 *[8-10-28]:[15]=-4*[-30]:15= 8 b) -(-(-(-5)))+(-4)*(8-12)-(-(-(-3)))*(-12):(-(-6))=5+ (-4)*(-4)+3*(-12):6=5+ 16+6=27 c) -[-(-10+17)-8]:[-4+3*(-5)*(-2);10-2]+(-7)=-[-7-8]:[-4+30/10 -2]-7= 15: [ -4+3-2] -7 =15:[-3] -7 = -5-7=-12