Oblicz stosując prawa działań na potęgach a)(2,4)^-3 : (0,6)^-3 f)(1i2/3)^-8 x (0.6)^-8

[latex]a) (2,4)^{-3}:(0,6)^{-3} = (2,4:0,6)^{-3} = 4^{-3} = (frac{1}{4})^{3} = frac{1}{64}\\b) (1frac{2}{3})^{-8}*(0,6)^{-8} = (frac{5}{3})^{-8}*(frac{3}{5})^{-8} = (frac{5}{3}*frac{3}{5})^{-8} = 1^{-8} = 1[/latex]

a)  (125)^ -³  ÷(35)^ -³ =(512 ÷53)³ =(512 *35)³ =14³ =164 b)  (53)^8 *(35)^ -8 =(53 *35) ^-8=11^ -8 =1