Rozwiąż układy równań metodą podstawiania: 1) [ 3(x-y) + 4x = 8 [ 3(x-5y) = 5- 9y 2) [3(2x-1)+ 4(y-2) = 9 [2(5x -1) + 3y = 5(3x+y) +2 PS. " [ " - oznacza klamerkę ;) Z góry dziękuje

1) [3(x-y)+4x=8 [3(x-5y)=5-9y [3x-3y+4x=8 [3x-15y=5-9y [7x-3y=8 [3x-15y+9y=5 [7x-3y=8 [3x-6y=5 [7x=8+3y/:7 [3x-6y=5 [x=8/7 + 3/7y [3x-6y=5 [x=8/7+3/7y [3(8/7+3/7y)-6y=5 [x=8/7+3/7y [24/7+9/7y-6y=5 [x=8/7+3/7y [24/7-4 5/7y=5 [x=8/7+3/7y [-4 5/7y=5-24/7 [x=8/7+3/7y [-4 5/7y= 1 4/7 /: (-4 5/7) [x=8/7+ 3/7y [y=11 7 : (-337) [x=8/7 + 3/7y [y= 11 7 * (-7 33) [x=8/7+3/7y [y= -1/3 [x=8/7+3/7y [y=-1/3 [x=8/7 + 3/7 * (-1/3) [y=-1/3 [x=8/7+(-1/7) [y=-1/3 [x=1 y=-1/3 2) [3(2x-1)+ 4(y-2) = 9 [2(5x -1) + 3y = 5(3x+y) +2 [6x-3+4y-8=9 [10x-2+3y=15x+5y+2 [6x+4y=9+8+3 [10x+3y-5y-15x=2+2 [6x+4y=20 [-5x-2y=4 [6x+4y=20 [-2y=4+5x/: (-2) [6x+4y=20 [y=-2-5/2x [6x+4(-2-5/2x)=20 [y=-2-5/2x [6x-8-10x=20 [y=-2-5/2x [-4x=20+8/:(-4) [y=-2-5/2x [x=-7 [y=-2+35/2 [x=-7 [y=34,5