zad1 a)3x+7/2+4=x/3 3(3x+7)=x(2+4) 9x+21=6x //-9x 21=-3x //÷-3 x=-7 b)1-8x/4+x-5/6=-3x //*12 12*1-8x/4+12*x-5/6=12*(-3x) 3(1-8x)+2(x-5)=-36x 3-24x+2x-10=-36x -7-22x=-36x //+22x -7=14x //÷14 x=-1/2 c)2-11x/10+8x+39/15-3x/2=0 //*30 30*2-11x/10+540x+30*39/15-30*3x/2=0 3(2-11x)+540x+2*39-15*3x=0 6-33x+540x+78-45x=0 84+462x=0 //-84 462x=-84 //÷462 x=2/11 po skroceniu ulamka zad2 a) 2/√6=2/√6*√6/√6=2√6/2=√6 b) 5/2√7=5*2√7/2√7*2√7=10√7/14=5√7/7 c) 5/6-√2=5√2/6-√2*√2=5√2/6-2=5√2/4 d) 4/√7+2=4√7/7+2√7=6√7/7
a) 3x-7/2+4= x/₃ |*6 18x-21+24=2x 18x-2x = -3 16x = -3 /:16 x=-3/16 b) 1-8x/4 + x-5/6= -3x |*12 12-24x+12x-10 = -36x -24x+12x+36x = -12+10 24x = -2 /:24 x =-2/24 x = -1/12 c) 2-11x/10 + 18x+39/15 - 3x/2=0 |*30 60-33x+540+78-45x = 0 -33x-45x = -60-540-78 -78x = -678 /:(-78) x = 8 54/78 x = 8 9/13 Zad. 2 usuń niewymierność z mianownika ułamka) a) 2/√6= 2√6 / 6 = √6 / 3 b)5/2√7= 5√7 / 14 c) 5/6-√2= 30+5√2 / 36-2 = 30+5√2 / 34 d) 4/√7+2= 28+4√2 / 49+7√2+7√2+2 = 28+4√2 / 51+14√2
