Oblicz, ile gramów kwasu octowego przereaguje ze 100 g NaOH ? Proszę o pomoc. ;)

xg (nad Ch3COOH), 100g(nad NaOH) CH3(indeks dolny)COOH+NaOH -> CH3(indeks dolny)COONa+H2(indeks dolny)O 1 mol (pod CH3COOH),1 mol(pod NaOH) 60g (pod CH3COOH), 40g(pod NaOH) 1 mol CH3COOH - 40 g NaOH xg CH3COOH- 100 g NaOH x= (100g*60g):40g= 150g