n^3-4n^2-2n+8= ?

n^3-4n^2-2n+8 = 3n - 8n - 2n + 8 = -7n + 8 prosze naj ;]

n^2(n-4)-2(n-4)=(n^2-2)(n-4)=(n-2)(n+2)(n-4) czyli n=2 lub n=-2 lub n=4

n^3-4n^2-2n+8 = 3n - 8n - 2n + 8 = -7n + 8