2 przykłady Dla - x= -2 a) (x²-3x-5)+(2x²+4x+6)-(-x²-x+2)= i drugi :)) dla - x=1 y= -5 b)-(5y+3x²)-(7x-4y)+12 Proszę o pomoc !!

a) x = -2 (x²-3x-5)+(2x²+4x+6)-(-x²-x+2)= (-2² -3 * (-2) - 5) + (2* (-2)² + 4 * (-2) + 6) - (-(-2)² - (-2) + 2) = (4 + 6 - 5) + (2 * 4 + (-8) + 6) - (-4 -2 + 2) = 5 + 6 + 4 = 15 b) x =1 y = -5 -(5y+3x²)-(7x-4y)+12 = - (5 * (-5) + 3 * 1²) - ( 7 * 1 - 4 * (-5) ) + 12 = (-25 + 3) - (7 + 20) + 12 = -22 - 27 + 12 = 5 + 12 = 17

1) [(-2)²-3*(-2)-5]+[2*(-2)²+4*(-2)+6]-[-(-2)²-(-2)+4]= =(4+6-5)+(8-8+6)-(-4+2+2)=5+6=11 2) -[5*(-5)+3*1²]-[7*1-4*(-5)]+12= =-(-25+3)-(7+20)+12=22-27+12=7