2,5(-2a+4b-5)-8(5a-b+jedna druga)-4+4(0,5a-2)= wyrażenia algebraiczne 6 klasa

2,5(-2a+4b-5)-8(5a-b+½)-4+4(0,5a-2)=-5a+10b-12,5-40a+8b-4+2a-8= -43a+18b-24,5

2,5 (-2a+4b-5) - 8(5a-b+½) - 4+ 4(0,5a-2) =- 5a + 10b - 12,5 - 40a +8b - 4+ 2a - 8= -43a + 18b - 24,5

2,5(-2a+4b-5)-8(5a-b+½)-4+4(0,5a-2)= (-5a+10b-12,5)-(40a-8b+4)-4+(2a-8)= -5a+10b-12,5-40a+8b-4-4+2a-8= -43a+18b-24,5