PILNE! Zadanie na dziś wieczór! PILNE! Oblicz wartość funkcji f(0), f(-1½), f(√₂), f(√₃+1), f(π), f(k), gdy jest ona określona wzorem: a) f(x)=2√₃x , b) f(x)=|x-√₂| , c) f(x)=(x+2)²-3 , d) f(x)=x/x-1 .

f(0), f(-1½), f(√₂), f(√₃+1), f(π), f(k) a) f(x)=2√₃*x f(0)=2√₃*0=0 f(-1½)=2√₃*(-1½)=-3√₃ f(√₂)=2√₃*√₂=2√₆ f(√₃+1)=2√₃*(√₃+1)=2*3+2√₃=6+2√₃ f(π)=2√₃π f(k)=2√₃*k b) f(x)=|x-√₂| f(0)=|x-√₂|=|0-√₂|=|-√₂|=√₂ f(-1½)=|x-√₂|=|-1½-√₂|=1½+√₂ f(√₂)=|x-√₂|=√₂-√₂=0 f(√₃+1)=|x-√₂|=|√₃+1-√₂|=√₃+1-√₂ f(π)=|x-√₂|=|π-√₂|=π-√₂ f(k)=|x-√₂|=k-√₂ c) f(x)=(x+2)²-3 f(0)=(x+2)²-3=1 f(-1½)=(-1½+2)²-3=¼-3=-2¾ f(√₂)=(√₂+2)²-3=2+4√₂+4-3=4√₂+3 f(√₃+1)=(√₃+1+2)²-3=(√₃+3)²-3=3+6√₃+9=6√₃+12 f(π)=(π+2)²-3 f(k)=(k+2)²-3 d) f(x)=x/x-1 f(0)=0 f(-1½)= -1½ / -1½-1= 3/5 f(√₂)=√₂/√₂-1 f(√₃+1)=√₃+1 / √₃+1-1= √₃+1 / √₃ * √₃/ √₃ = 3+√₃ / 3 f(π)=π/π-1 f(k)=k/k-1