Do 60g 12% r-ru dodano 20g H2O. Oblicz stężenie procentowe otrzymanego r-ru.

mr=60g cp=12% mw=20g cp1=? ------------------------------------------------------ cp=ms*100%/mr ms=cp*mr/100%=12%*60g/100%=7,2g mr1=mr+mw=60g+20g=80g cp1=ms*100%/mr1=7,2g*100%/80g=9%