Rozwiąż równanie: 2(u-5) + 15 =3(u - 4) + 10 2 (3a - 2) - 6 = 4,5 (2a - 1 ) + 0,5 -3 (y/3 + 1) - 2= 4 (1 - y)

A) 2u - 10 + 15 = 3u - 12 + 10 2u - 3u = -12 + 10 + 10 - 15 -u= - 7 / :(-1) u = 7 B) 6a - 4 - 6 = 9a - 4,5 + 0,5 6a - 9a = -4,5 + 0,5 + 4 + 6 - 3a = 6 /: (-3) a = -2 C) -3y/3 - 3 - 2 = 4 - 4y -3y/3 + 4y = 4 + 3 + 2 -3y/3 + 4y = 9 / *3 3(-3y/3 + 4y) = 9*3 -3y + 12 y = 27 9y = 27 / : 9 y = 3

2(u-5) + 15 =3(u - 4) + 10 2u-10+15=3u-12+10 2u+5=3u-2 -u=3 u=-3 2 (3a - 2) - 6 = 4,5 (2a - 1 ) + 0,5 6a-4-6=9a-4,5+0,5 6a-10=9a-4 -3a=6 a=-2 -3 (y/3 + 1) - 2= 4 (1 - y) -y-3-2=4-4y -y-5=4-4y -5y=9 y=-9/5 y=-1⅘