Zapisz w jak najprostszej postaci jak co to to sa sumy algebraiczne i trzeba je mnozyc 4(2a-b)(2a+4b)-(3a-2b)(3b-2a)= 2d do kwadratu -(3c-2d)(c-d)-c(c-2d)+2d do kwadratu

4(2a-b)(2a+4b)-(3a-2b)(3b-2a)= = 4 (4a²+8ab-2ab-4b²) - (9ab-6a²-6b²+4ab) = = 4 (4a²+6ab-4b²) - (13ab-6a²-6b²) = = 16a²+24ab-16b² -13ab+6a²+6b² = = 22a²+11ab -10b² 2d²-(3c-2d)(c-d)-c(c-2d)+2d² = =2d²-(3c²-3cd-2cd+2d²) -c²+2cd+2d²= =2d²-(3c²-5cd+2d²)-c²+2cd+2d²= =2d²-3c²+5cd-2d²-c²+2cd+2d² = =2d²-4c²+7cd