cp=50% dr=1,3g/cm³ Vr=1l=1dm³=1000cm³ dw=1g/cm³ Vw=500cm³ cp1=? --------------------------------------------------- mr=dr*Vr=1,3g/cm³*1000cm³=1300g cp=ms*100%/mr ms=cp*mr/100%=50%*1300g/100%=650g mw=dw*Vw=1g/cm³*500cm³=500g mr1=mr+mw=1300g+500g=1800g cp1=ms*100%/mr=650g*100%/1800g=36,1%
v=1 litr=1000cm3 d=1,3g/cm3 d=m/v m=v*d m=1000*1,3 m=1300g Z def. stęż. procent. 50g kwasu-----100g roztworu xg kwasu-------1300g roztworu x=50*1300/100 x=650g kwasu Gęstość wody d=1g/cm3, więc 500cm3=500g Po dolaniu 500g wody: 650g kwasu-------1800g roztworu(1300g+500g) xg kwasu----------100g roztworu x=650*100/1800 x=36,11g x=36,11% Stezenie procentowe otrzymanego roztworu wynosi 36,11%
