(a+b)(3a+3b+2)+(2a+b)²= (x+3b-5)(3x+3y)+(3x+2y-1)(x+3y)= 2(2+3b-5)(a+b-3)-(a+b)²= 3(2x+3y)(3x-2y)+(3x+4)²+(3x-3y-2)(x+y)= Please!!!!!!!!

(a+b)(3a+3b+2)+(2a+b)²= (x+3b-5)(3x+3y)+(3x+2y-1)(x+3y)= 2(2+3b-5)(a+b-3)-(a+b)²= 3(2x+3y)(3x-2y)+(3x+4)²+(3x-3y-2)(x+y)= Please!!!!!!!!
Odpowiedź

^ oznacza do kwadratu (a+b)(3a+3b+2)+(2a+b)²= =3a^+3ab+2a+3ab+3b^+2b-4a^+4ab+b^= =7a^+2a+10ab+4b^+2b (x+3b-5)(3x+3y)+(3x+2y-1)(x+3y)= =x3^+9xb-15x+3xy+9yb-15y+3x^+9xy+2xy+6y^-x-3y= =6x^+9xb-16x+6y^+14xy+9yb-18y 2(2+3b-5)(a+b-3)-(a+b)²= =4a+4b-12+6ab+6b^-18b-10a-10b+30-a^-2ab-b^= =-a^-6a+4ab+5b^-24b+18 3(2x+3y)(3x-2y)+(3x+4)²+(3x-3y-2)(x+y)= =3(6x^-4xy+9xy-6y^)+(9x^+24x+16)+(3x^-3xy-2x+3xy-3y^-2y)= =18x^+15xy-18y^+9x^+24x+16+3x^-2x-3y^-2y= =30x^+15xy+22x-21y^-2y+16

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