jak rozwiażąć ten uklad równan? x+y=12 10 x +y + 54 = 10y+x

x+y=12 10 x +y + 54 = 10y+x x+y=12 10x+y-10y-x=-54 x+y=12 9x-9y=-54 /:9 x+y=12 x-y=-6 + ----------- 2x=6 /:2 x=3 3+y=12 y=9 x=3 y=9

x+y=12 10x+y+54=10y+x x=12-y 10(12-y)+y+54=10y+12-y x=12-y 120-10y+y+54=9y+12 x=12-y 174-9y=9y+12 x=12-y -9y-9y=12-174 x=12-y -18y=-162 /-18 x=12-y y=9 x=12-9 y=9 x=3 y=9

odp masz w zalaczniku