x(x-1)-3(x²-x)= 5a(a-3)-3a(a-5)= 3x(x+1/3y)-2y(1/2x-1/2)=

x(x-1)-3(x²-x)= 5a(a-3)-3a(a-5)= 3x(x+1/3y)-2y(1/2x-1/2)=
Odpowiedź

x(x-1)-3(x²-x)=x²-x-3x²+3x=-2x²+2x 5a(a-3)-3a(a-5)=5a²-15a-3a²+15a=2a² 3x(x+1/3y)-2y(1/2x-1/2)= 3x²+xy-xy+y=3x²+y

x²-x-3x²+3x=-2x²+2x 5a²-15a-3a²+15a=2a² 3x²+xy-xy+y=3x²+y

x(x-1)-3(x²-x) = x²-x-3x²+3x = -2x²+2x 5a(a-3)-3a(a-5) = 5a²-15a-3a²+15a = 2a² 3x(x+1/3y)-2y(1/2x-1/2) = 3x²+xy-xy+y = 3x²+y

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