y+3/2-(1-y)=3,5 1/5(y-3)-2/3(y-3/5)+1/3=2/5-1/3(2y-3) 2y+4:4=1/2y+1 y-2:3+1/15-2y-5:3=8-4y:5 y-5/2+(2y+3 :5)+1/3=y+7:15+y/2 dzieki prosze o jak najszybsze rozwiązanie tego zadania :)) to zadanie 16 na stronie 73 zbiór zadań klasa 1 gimnazjum

y+3/2-(1-y)=3,5 y+3/2-1+y =35/10 | *10 10y + 15 -10 +10y = 35 10y + 5 +10y = 35 20 y = 35 - 5 20y = 30 | : 20 y = 1,5 1/5(y-3)-2/3(y-3/5)+1/3=2/5-1/3(2y-3) 1/5y - 3/5 -2/3y + 6/15 + 1/3 = 2/5 - 2/3 y +1 | *15 3y -9 - 10y + 6 + 5 = 6 - 10y +15 3y - 10 y + 10y = 21 + 9 - 11 3y = 19 y = 6 1/3 2y+4:4=1/2y+1 2y + 4 * 1/4 = 1/2y +1 2y + 1 = 1/2y + 1 2y - 1/2 y = 1 -1 1,5y = 0 |: 1,5 y = 0 y-2:3+1/15-2y-5:3=8-4y:5 y - 2 * 1/3 + 1/15 -2y - 5* 1/3 = 8 - 4y *1/5 y - 2/3 + 1/15 -2y - 5/3 = 8 - 4/5y |*15 15y - 10 + 1 - 2y -25 = 8- 12y 13y +12y = 8 +34 25y = 44 | :25 y= 1 19/44