zad. a) (4-2x) - (x+3) = (x-5) + (-3 - x) b) (3- 2x) + (3x+4) =- (3-2x) + (5x + 4) proszę ! :D

(4-2x) - (x+3) = (x-5) + (-3 - x) 4-2x-x-3=x-5-3-x -2x-x-x+x=-5-3+3-4 -3x=-9|*(-1) 3x=9 x=3 (3- 2x) + (3x+4) =- (3-2x) + (5x + 4) 3-2x+3x+4=-3+2x+5x+4 -2x+3x-2x-5x=-3+4-4-3 -6x=-6|*(-1) 6x=6 x=1

a) (4-2x) - (x+3)=(x-5)+(-3-x) 4-2x-x-3=x-5-3-x -3x-x+x=-8-4+3 -3x=-9/(-3) x=3 b) (3-2x)+(3x+4)=-(3-2x)+(5x+4) 3-2x+3x+4=-3+2x+5x+4 -2x+3x-2x-5x=-3+4-3-4 -6x=-6/(-6) x=1

a) (4-2x) - (x+3)=(x-5)+(-3-x) 4-2x-x-3=x-5-3-x -3x-x+x=-8-4+3 -3x=-9/(-3) x=3 b) (3-2x)+(3x+4)=-(3-2x)+(5x+4) 3-2x+3x+4=-3+2x+5x+4 -2x+3x-2x-5x=-3+4-3-4 -6x=-6/(-6) x=1