Rozwiąż równanie: a)(x-2)³-3x(2-x)=x²(x-3)+10 b)x/5+3=⅔+x+1/5

odp 1 x³-6x²+12x-8-6x+3x²=x³-3x²+10 6x=18 x=3 odp 2 x/5+3=⅔+x+1/5 /*15 3x+45=10+15x+3 12x=32 x=2 i 2/3

a) (x-2)³-3x(2-x)=x²(x-3)+10 (x -2)²(x -2) +3x(x -2) = x² ( x -3) + 10 (x -2)[( x -2)² +3x] = x³ -3x² +10 (x-2)[ x² -4x +4 +3x] = x³ -3x² +10 (x-2) (x² -x +4) = x³ -3x² +10 x³ -x² +4x -2x² +2x -8 -x³ +3x² -10 = 0 +6x -18 = 0 6x = 18 x = 18 :6 x = 3 b)x/5+3=⅔+x+1/5 /15 3x + 45 = 10 + 15x +3 3x -15x = 13 -45 -12x = - 32 x = (-32): (-12) x = 2 i 8/12 x = 2 i 2/3