√3(2y + 3) - 3y(2 - √3) = 0 2√3 y + 3√3 - 6y + 3√3 y = 0 - 6y + 5√3 y = 3√3 y = 3√3/(5√3 - 6) = [3√3(5√3 + 6)]/(25*3 - 36) = [3√3(6 + 5√3)]/39 = √3(6 + 5√3)/13 2x(√2 + 1) = √2(3x - 7) 2√2 x + 2x = 3√2 x - 7√2 x(2 - √2) = - 7√2 |:√2 x(√2 - 1) = - 7 x = - 7/(√2 - 1) = - 7(√2 + 1)/(2 - 1) = - 7(√2 + 1) 2√5t - 5 = 3√5(8 - 7t) |:√5 2t - √5 = 24 - 21t 23t = 24 + √5 t = (24 + √5)/23 jak masz pytania to pisz na pw
Rozwiąż równania: √3(2y+3)-3y(2-√3)=0 2√3y+3√3-6y+3y√3=0 5√3y-6y=3√3 y(5√3-6)=3√3 y=3√3/(5√3-6) y=3√3(5√3+6)/(5√3-6)(5√3+6) y=3√3(5√3+6)/(75-36) y=3√3(5√3+6)/(39) y=√3(5√3+6)/13 2x(√2+1)=√2(3x-7) 2x√2+2x=3√2x-7√2 2x-1√2x=-7√2 x(2-1√2)=-7√2 x=-7√2/(2-1√2) x=-7√2(2+1√2)/(2-1√2)(2+1√2) x=-7√2(2+1√2)/(4-2) x=-7√2(2+1√2)/2 2√5t-5=3√5(8-7t) 2√5t-5=24√5-21√5t 2√5t+21√5t=24√5+5 23√5t=24√5+5 t=(24√5+5)/23√5 t=(24√5+5)√5/23√5*√5 t=(120+5√5)/115
