zad.1 2/3t÷(-3)= zad.2 a)-(4x+3-½y)= b)-5(-3a+b-0,7)= c)-(-½t-z-6)= zad.3 a) (2x+8)÷(-2)= b) (a-10)/5= c)9x-7y-3/3= d)(-4z-2t)/1/2= e)(4w-2+3u)/(-1 1/3) f)0,6w+10y-1/(-o,2= pilne

zad.1 2/3t÷(-3)= zad.2 a)-(4x+3-½y)= b)-5(-3a+b-0,7)= c)-(-½t-z-6)= zad.3 a) (2x+8)÷(-2)= b) (a-10)/5= c)9x-7y-3/3= d)(-4z-2t)/1/2= e)(4w-2+3u)/(-1 1/3) f)0,6w+10y-1/(-o,2= pilne
Odpowiedź

zad.1 2/3t÷(-3)=2/6t zad.2 a)-(4x+3-½y)= -4x-3+1/2y b)-5(-3a+b-0,7)=15a-5b+3,5 c)-(-½t-z-6)=1/2t+z+6 zad.3 a) (2x+8)÷(-2)=-x-4 b) (a-10)/5=1/5a-2 c)9x-7y-3/3=9x-7y-1 d)(-4z-2t)/1/2=-8z-4 e)(4w-2+3u)/(-1 1/3)=12/11w-6/11+9/11u f)0,6w+10y-1/(-o,2)=0,6w+10y+5

Zad.1 =2/3t*(-1/3)=(-2/9) Zad.2 a)=-4x-3+1/2y=1/2y-4x-3 b)=15a-5b+3.5 c)=1/2t+z+6 Zad.3 a)=(2x+8)*(-1/2)=-1x-4 b)----- c)

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