2(4-√2) (4+√2)+2 (4+√2)10+2(4-√2)10=

2(4-√2)(4+√2) + 2(4+√2)10 + 2(4-√2)10= 2(16-2) + 80 + 20√2 + 80 -20√2= 28 +80 +80= 188

2(4-√2) (4+√2)+2 (4+√2)10+2(4-√2)10= = 2[ 4² -(√2)²] + 2(4 + √2)¹⁺ + 2( 4 -√2) ¹⁺= = 2[( 16 - 2) + (4 + √2)¹⁺ + ( 4 -√2) ¹⁺] = = 2[ 14 + (4 + √2)¹⁺ + ( 4 -√2) ¹⁺] Nie wiem czy za nawiasem jest do potegi 10 czy pomnożone przez 10 ? 2(4-√2) (4+√2)+2 (4+√2)10+2(4-√2)10= = 2(16 -2) + 20(4 + √2) + 20( 4 -√2) = = 2*14 + 80 + 20√2 + 80 - 20√2 = = 28 +160= = 188