napisz rownanie reakcju zgodnie ze schematem CH3-CH3-->A-->B-->C-->D-->E i tak: nad 1--> ma byc Br2 a pod swiatlo nad2 --> KOH 3 --> CuO 4 --> Ag2O 5 --> MgO

CH3-CH3 + Br2----->CH3-CH2-Br + HBr CH3-CH2-Br + KOH---->CH3-CH2-OH + KBr CH3-CH2-OH + CuO---->CH3-CHO + Cu + H2O CH3-CHO + Ag2O---->CH3-COOH + 2Ag 2CH3-COOH + MgO---->(CH3COO)2Mg + H2O PROSZĘ BARDZO