(x-3)^2-16=0

(x-3)^2-16=0 <=> x^2-6x+9-16=0 <=> x^2-6x-7=0 delta=36-4*1*(-7)=64 pierwiastek z delta=8 x1=(6-8)/2=-2/2=-1 x2=(6+8)/2=14/2=7 Odp: x=-1 lub x=7

(x-3)²-16=0 x²-6x+9-16=0 x²-6x-7=0 liczymy delte Δ=b²-4ac Δ=(-6)²-4*1*(-7) Δ=36+28 Δ=64 √Δ=8 x₁=-b-√Δ/ 2a x₁=6-8/ 2*1 x₁=-2/2 x₁=-1 x₂=-b+√Δ/ 2a x₂=6+8/ 2*1 x₂=14/2 x₂=7

(x-3)^2-16=0 x^2 -6x +9 -16=0 x^2 -6x -7 =0 delta = b^2 -4ac delta = 36 - 4*1*(-7) = 64 delta= 8 X1 = (-b- delta)/ 2a x1 = (6 - 8)/2 x1= -2/2 x1 = -1 x2 = (-b+ delta)/2a x2= (6+8)/2 x2 = 14:2 x2= 7