Obliczyć 9^(log(3)4+log(1/3)2)=? log(x)4>2

Obliczyć 9^(log(3)4+log(1/3)2)=? 9^(log(3)4+log(1/3)2)=9^log(3)4 *9^log(1/3)2=3^2log(3)4 *3^2log(1/3)2= 3^log(3)16 *3^log(1/3)4=3^(log(3)16 +log(1/3)4)= 3^(log(3)16 +log(3)4/log(3) 1/3)=3^(log(3)16 +log(3)4/-1)= 3^(log(3)16 -log(3)4)=3^(log(3)16:4)=3^(log(3)4)=4 log(x)4>2 4>x² /√ gdy x>1 2>IxI x∈(-2;2) i x>1 czyli: x∈(1;2) 4