oblicz objętość stożków przedstawionych na rysunkach pilne

1. V = 1/3πr²H l = 10√2 śr = 10 r = 5 obliczam H z tw. Pitagorasa H²+5² = (10√2)² H² = 100*2-25 H² = 200-25 H² = 175 H = √175 = √25*7 = 5√7 V = 1/3πr²H V = 1/3π*5²*5√7 V = (125/3)π√7 2. V = 1/3πr²H l = 10 r = 5 obliczam H z tw. Pitagorasa H²+5² = 10² H² = 100-25 H² = 75 H = √75 = √25*3 = 5√3 V = 1/3πr²H V = 1/3π*5²*5√3 V = (125/3)π√3