w jakim czasie worek cemetu zostanie podniesieiony na wysokosc 48m jezeli uzyto silnika o mocy 300W obliczenia ;] Masa worka = 25kg

P = W/t |*t P*t = W|:P t = W/P - wzór z którego będziemy korzystać ;) m = 25 kg h = s = 48m P = 300 W g = 10 N/kg W = F*s F = m*g F = 25*10 F = 250 N [F] = [kg* N/kg] = [N] W = 250* 48 W = 12 000 J [W] = [N*m] = [J] t = W/P t = 12000/300 t = 40s [t] = [J/W] = [J / J*s] = [s]