suma dwóch liczb wynosi 512, a róznica tych liczb wynosi 96.jakie to liczby?

x+y = 512 x-y = 96 x = 512-y x-y = 96 512-y-y = 96 x = 512-y 512-2y = 96 x = 512-y -2y = -416 /:(-2) x = 512-y y = 208 x = 512-y x = 512-208 y = 208 x = 304 y = 208

x-jedna liczba y-druga liczba x+y=512 x=512-y x-y=96 512-y-y=96 -2y=96-512 -2y=-416/:(-2) y=208 x=512-y x=512-208 x=304 odp.jedna liczba to 304,a druga to 208 spr.x-y=96 304-208=96 96-96 L=P x+y=512 304+208=512 512=512 L=P

x+y=512} x-y=96} x=512-y} (512-y)-y=96} x=512-y} 512-2y=96} x=512-y} -2y=96-512} x=512-y} -2y=--416|:(-2)} x=512-y} y=208} y=208} x=512-208} y=208} x=304}