Rozwiąż równanie a) 12y - (y+5) = 10y - 1 b) 2 (u-5) + 15 = 3(u-4) + 10

a) 12y - (y+5) = 10y - 1 12y-y-5=10-1 12y-y-10y=1+5 y=6 b) 2 (u-5) + 15 = 3(u-4) + 10 2u-10+15=3u-2+10 2u-3u=-12+10-10+15 -u=3 :(-1) u=-3

a) 12y - (y+5) = 10y - 1 12y-y-5=10y-1 11y-10y=5-1 y=4 b) 2 (u-5) + 15 = 3(u-4) + 10 2u-10+15=3u-12+10 2u-3u=10-15-12+10 -u=-7/(-1) u=7

a) 12y-(y+5)=10y-1 ; 12y-y-5=10y-1 ; 11y-10y=-1+5 ; y=4 ; b)2(u-5)+15=3(u-4)+10 ;2u-10=3u-12+10 ; 2u-3u=-12+10+10 ;-u=8 ;u=-8