Oblicz w taki sposób np: Mg(OH₂) mMg+2 x mO +2 x mH=24u+2x 16u+2x 1u=58u x =to razy 1.Br₂, 2. KCl, 3.Ag₂O, 4.Fe₂S₃, 5 K₂SO₃, 6.Al₂(SO₄)₃, 7.CuO 8.Fe₂O₃, 9. Na₂CO₃, 10.H₂SO₄, 11.Ca(OH)₂ 12.Al₂(SO₃)₃ Prosze o pomoc plis

1. 2 x mBr = 2 x 80u = 160u 2. mK + mCl = 39u + 35u = 74u 3. 2 x mAg + mO = 2 x 108u + 16u = 216u + 16u = 232u 4. 2 x mFe + 3 x mS = 2 x 56u + 3 x 32u = 112u + 96u = 208u 5. 2 x mK + 3 x mS + 3 x mO = 2 x 39u + 3 x 32u + 3 x 16u = 78u + 96u + 48u = 222u 6. 2 x mAl + 7 x mS + 7 x mO = 2 x 27u + 7 x 32u + 7 x 16u = 54u + 224 u + 112u = 390u 7. mCu + mO = 64u + 16u = 80u 8. 2 x mFe + 3 x mO = 2 x 56u + 3 x 16u = 112u + 48u = 160u 9. 2 x mNa + 3 x mC + 3 x mO = 2 x 23u + 3 x 12u + 3 x 16u = 46u + 36u + 48u = 130u 10. 2 x mH + 4 x mS + 4 x mO = 2 x 1u + 4 x 32u + 4 x 16 = 2u + 128u + 64u = 194u 11. mCa + 2 x mO + 2 x mH = 40u + 2 x 16u + 2 x 1u = 40u + 32u + 2u = 74u 12. 2 x mAl + 6 x mS + 6 x mO = 2 x 27u + 6 x 32u + 6 x 16u = 54u + 192u + 96u = 342u proszę bardzo ; )