1/4z+(z-6)=2/3(z-2) HELP MUSZE TO MIEC JAK NAJSZYBCIEJ

[latex]frac{1}{4}z+(z-6)=frac{2}{3}(z-2) /cdot12\3z+12(z-6)=8(z-2)\3z+12z-72=8z-16\3z-8z+12z=-16+72\7z=56 / : 7\z=8[/latex]

[latex]frac{1}{4}z+(z-6)=frac{2}{3}(z-2) / cdot 12[/latex] [latex]3z+12 cdot(z-6)= 8 cdot (z-2) [/latex] [latex]3z+12z-72= 8z-16 [/latex] [latex]15z-8z = -16 + 72[/latex] [latex]7z = 56 / : 7[/latex] [latex]z = 8[/latex]