(2x-3)^2-(x-+2)(x-2)+8/7=(x+5)^2-x^2-2/3x ^2 to sa potegi

(2x-3)²2-(x-+2)(x-2)+8/7=(x+5)²2-x²2-2/3x (4x²+12x-9)*2-(x²-4)+8/7=(x²+10x+25)*2-x²*2-2/3x 8x²+24x-18-x²+4+8/7=2x²+20x+50-2x²-2/3x 8x²-x²-2x²+2x²+24x-20x+2/3x=50+18-4-8/7 7x²+4i2/3x=63i6/7