rozwiąż równania a 4-(2x-5)4(2x-1)-2(3x+2) d (x-1)/3-(2x+5)/6>=1 e (x-1)do kwadratu-(x+2)<=3(1-2x) f (x-3)(x+3)-6(x-3)<=(4-x)do kwadratu+2(x-5)

a 4-(2x-5)4(2x-1)-2(3x+2) 7x-21+20-5x>8x-4-6x-4 2x-1>2x-8 0>-7 d (x-1)/3-(2x+5)/6>=1 //*6 2x-2-2x+5>-1 0>-4 e (x-1)do kwadratu-(x+2)<=3(1-2x) x²-2x+1-x-2<-3-6x x²--3x-1<-3-6x x²+3x<-2 x²-3x+2<0 Δ=b²-4ac=9-8=1 x1=-b-√Δ/2a=3-1/2=2-2=1 x2=-b+√Δ/2a=3+1/2=4/2=2 (x-1)(x-2)<0 <=> x<1 lub x<2 f (x-3)(x+3)-6(x-3)<=(4-x)do kwadratu+2(x-5) x²+3x-3x-9-6x+18<16-8x+x²+2x-10 -6x+9<6-6x 0<-3