z4. do 400g 5% roztworu chlorku amonu dolano 100g wody. oblicz stężenie procentowe otrzymanego roztworu!! plis

mr1=400g Cp1=5% mr=100g ms=? mr2=? Cp2=? Cp1=ms/mr1*100% ms=Cp1*mr1/100% ms=20g mr2=100g+400g=500g Cp2=ms*100%/mr2 Cp2=20g*100%/500g Cp2=4%

Cp = ms/mr * 100% Cp = 20/500*100% Cp = 4%