proszę o pomoc!!!!!!!!!!! a) -4x² - 16x + 9 = 0 b) 2(2x – 3) (x + 1) – 5(x-1)² = 2(x-2)(x-1) c) -x² - 3x + 4 ≥ 0 d) x² -7x + 12 > 0 e) -4a² - 16a +9 < 0 f) x² -6x + 9 ≤ 0

ODP: a i e są takie same, tylko literki są inne b) 2(2x – 3) (x + 1) – 5(x-1)² = 2(x-2)(x-1) c) -x² - 3x + 4 ≥ 0 Δ=b²-4ac=(-3)²-4x(-1)x4=9+16=25 √Δ=√25=5 x1= -b- √Δ/2a=3-5/2x(-1)= -2/-2= 1 x2= -b+√Δ/2a=3+5/2x(-1)= 8/-2= -4 d) x² -7x + 12 > 0 Δ=b²-4ac= (-7)² - 4×1×12=49-48=1 x1= -b- √Δ/2a= 7-1/2×1= 6/2=3 x2= -b+ √Δ/2a= 7+1/2x1=8/2=4 e) -4a² - 16a +9 < 0 Δ=b²-4ac= (-16)² -4×(-4)×9=256+144=400 √Δ=√400=√100x4= √10√4=20√2 x1= -b- √Δ/2a=16-20√2/2x(-4)=16-20√2/-8=2-20√2 x2= -b+√Δ/2a=16+20√2/2x(-4)=16+20√2/-8=2+20√2 f) x² -6x + 9 ≤ 0 Δ=b²-4ac=(-6)² -4x1x9=36-36=0 x0= -b/2a=6/2x1= 6/2=3