Witaj :) 1. dane λ=825 nm, h=6,62*19(-34)Js, szukane E ------------------------------------------ E = h*f.........λ=cT.......T=1/f........λ=c/f.......f=c/λ E = hc/λ = 6,62*10(-34)Js *3*10(8)m/s //825*10(-9)m = 2,4*10(-19)J = E = 2,4*10(-19)J //1,6*10(-19)J/eV = 1,5 eV. Enerrgia tego fotonu wynosi 2,4*10(-19)J lub 1,5 eV. 2. dane f=100MHz, h=6,62*18(-34)Js, c=3*10(8)m/s, szukane p ----------------------------------------------- p = h/λ........λ=c/f p = hf/c = 6,62*10(-34)Js *10(8)Hz //3*10(8)m/s = 2,21*10(-34)kgm/s Pęd takiego kwantu wynosi ok. 2,21*10(-34)kgm/s. Semper in altum.................................pozdrawiam :)
