rozwiąż równania: a 5(x-1)+2x=2(x+2)+6 b x+4-5(x-8)=x-6 c 6x-(x-1)=6 d 2(x-1)+3(x-2)=7 e 3(x+2)+2(2x-3)=x-12 f x(x-2)-(X2-2x-3)=2x+1 w f X w drugim nawiasie jest do potęgi drugiej!

a) 5(x-1)+2x=2(x+2)+6 5x-5+2x=2x+4+6 5x+2x-2x=5+4+6 5x=15 /:5 x=3 b)x+4-5(x-8)=x-6 x+4-5x-40=x-6 x-5x-x=40-4-6 -5x=30 /:(-5) x=-6 c) 6x-(x-1)=6 6x-x+1=6 6x-x=6-1 5x=5 /:5 x=1 d)2(x-1)+3(x-2)=7 2x-2+3x-6=7 2x+3x=7+6+2 5x=15 /:5 x=3 e)3(x+2)+2(2x-3)=x-12 3x+6+4x-6=x-12 3x+4x-x=6-6-12 6x=-12 /:6 x=-2 f)x(x-2)-(X2-2x-3)=2x+1 x2-2x-x2+2x+3=2x+1 x2-x2-2x+2x-2x=1-3 -2x=-2 /:(-2) x=1